A 2 Cavity Klystrom has the following parameters: $V_{0}=1000 \mathrm{~V}, R_{0}=30 \mathrm{k} \Omega$, $I_{0}=20 \mathrm{~mA}, f=2 \mathrm{GHz}, d=1 \mathrm{~mm}, L=4 \mathrm{~cm}, R_{s h}=30 \mathrm{k} \Omega$. (c) Find the efficiency of the amplifier, neglecting beam loading.

Explanation

The efficiency of the amplifier is the ratio of the output power to the input power. It is calculated using the given parameters.