(a) A metallic rod 10 mm is diameter is tested under axial pull of 10 kN . The diameter of the rod is reduced by 0.002 mm . Modulus of rigidity of the material of the rod is $0.5 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, Find the other module. $\quad 10$

Explanation

The modulus of rigidity is given by G = E / (2 * (1 + ν)) where ν is Poisson's ratio. Given E = 0.5 * 10^5 N/mm^2 and ν = 0.3, we can calculate G.