(a) A right handed monofilar helical antenna has 15 turns, 100 mm diameter and 60 mm turn spacing. The frequency is 1.2 GHz . Find out: (i) HPBW (ii) Gain (iii) State of Polarization.
Explanation
The HPBW of a helical antenna is given by HPBW = 52° + 0.3n, where n is the number of turns. For a 15-turn helical antenna, HPBW = 52° + 0.3*15 = 70°. The gain of a helical antenna is given by Gain = 2.15 + 0.5n, where n is the number of turns. For a 15-turn helical antenna, Gain = 2.15 + 0.5*15 = 2.15 dBi. The state of polarization of a helical antenna is linear.
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