A lift has an upward acceleration of $1.2 \mathrm{~m} / \mathrm{s}^{2}$. What force will a man weighing 750 N exerts on the floor of the lift? What force would he exert if the lift had an acceleration of $1.2 \mathrm{~m} / \mathrm{s}^{2}$ downwards? What upward acceleration would cause his weight to exert a force of 960 N on the floor.
Explanation
To find the force exerted by the man on the floor of the lift, we need to use the equation of motion for the man. We can then solve for the force exerted by the man on the floor of the lift. We can also solve for the force exerted by the man on the floor of the lift if the lift has an acceleration of 1.2 m/s^2 downwards. Finally, we can solve for the upward acceleration of the lift that would cause the weight of the man to exert a force of 960 N on the floor.
⬆ Related Topic
📘 Syllabus
View KERALA UNIVERSITY Class 1 Syllabus →
📝 Practice Questions
Practice Previous Year Questions →
🤖 Practice with AI
Generate Practice Question Paper →
📚 Related Concepts
- Find the relation between $\alpha$ and $\beta$ of BJT.
- Compare and contrast FET and BJT
- Implement the following function using minimum number of logic gates $Y=A \bar{B}+C D+\bar{B} \bar{D}+A D$.
- What are the characteristics of an ideal OP AMP?
- Explain the term biasing and what is the need for proper biasing?