A line segment joining $\mathrm{P}(2,-3)$ and $\mathrm{Q}(0,-1)$ is cut by the $x$-axis at the point $R$. A line $A B$ cuts the $y$ axis at $T(0,6)$ and is perpendicular to $P Q$ at $S$. Find the: equation of line PQ
Explanation
To find the equation of line PQ, we need to find the slope of the line and then use the point-slope form of a linear equation. The slope of the line is the change in y divided by the change in x, which is (-1 - (-3)) / (0 - 2) = 1. The point-slope form of a linear equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We can use the point P(2, -3) to find the equation of the line. Plugging in the values, we get y - (-3) = 1(x - 2), which simplifies to y + 3 = -2(x - 2).
⬆ Related Topic
📘 Syllabus
📝 Practice Questions
Practice Previous Year Questions →
🤖 Practice with AI
Generate Practice Question Paper →