A pulley system has a velocity ratio 5 . Draw a neat labelled diagram of the pulley system to lift a load by applying the effort in a convenient direction. Mark the tension in your diagram. If a load of 10 kgf is pulled up by a distance of 2 m in 10 s , calculate the power developed by the effort (given $g=10 \mathrm{~m} \mathrm{~s}^{-2}$ ).
Explanation
To calculate the power developed by the effort, we use the formula: Power = Work / Time. The work done is given by the product of the force and the distance moved. In this case, the force is the weight of the load (10 kgf) and the distance is 2 m. The time taken is 10 s. Therefore, Power = (10 kgf x 2 m) / 10 s = 20 W.
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