A radioactive nucleus X emits an alpha particle followed by two beta particles and forms nucleus Y . If the atomic number of Y is 80 then what is the atomic number of X ?
Explanation
Let's assume the atomic number of X is Z. When X emits an alpha particle, its atomic number decreases by 2, so the atomic number of the nucleus after emitting the alpha particle is Z - 2. When this nucleus emits two beta particles, its atomic number increases by 2, so the atomic number of Y is Z - 2 + 2 = Z. We are given that the atomic number of Y is 80, so Z = 80. Therefore, the atomic number of X is 82.
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