Calculate the reading of A when $\quad \mathrm{K}$ is closed.
Explanation
When K is closed, the circuit is complete and the current flows through the ammeter A. Since the ammeter is in series with the circuit, the reading of A will be equal to the total current flowing through the circuit. From the diagram, we can see that the circuit consists of a power source, a variable resistor, and a fixed resistor. When K is closed, the variable resistor is bypassed and the circuit becomes a simple series circuit with a power source and a fixed resistor. The total resistance of the circuit is 3 ohms and the power source is 6 V. Using Ohm's law, we can calculate the total current flowing through the circuit as I = V/R = 6/3 = 2 A. Therefore, the reading of A will be 2 A when K is closed.
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