Can the number $8^{n}, n$ being a natural number, end with the digit 0 ? Give reasons. This section consists of 6 questions of 3 marks each.
Explanation
For a number to end with the digit 0, it must be divisible by 10. Since 8^n is always divisible by 8, it can never be divisible by 10, unless n is a multiple of 5. However, even in that case, the number will end with the digit 8, not 0.
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