B.TECH - Semester 6 computer aided design Question Paper 2013 (apr)
Practice authentic previous year university questions for better exam preparation.
Sample Questions
- Write the transformation matrices for rotation about z and x axes in homogenous coordinates
- What are the benefits of CAD over conventional design?
- What do you mean by Geometric modeling
- What is homogeneous coordinate system and explain it use?
- What is composite transformation in computer graphics
- What do you mean by windowing and clipping?
- Explain the requirements of a good graphics software
- What is discretisation? Sketch two types elements for two dimensional domain.
- Define shape functions and write their properties.
- What is meant by stiffness matrix? ( $\mathbf{1 0} \boldsymbol{\times} \mathbf{2} \boldsymbol{=} \mathbf{2 0}$ Marks) P.T.O. Answer any one full question from each Module. Each question carries 20 Marks.
- (a) Explain (i) Wireframe modelling (ii) Surface modelling ..... 10
- (b) Illustrate the various methods for solid model representation. ..... 10
- (a) Discuss the any five features of solid modelling packages. ..... 10
- (b) What are the applications of computer in Design? ..... 10 Module II
- (a) Discuss the various 3D geometric transformations. ..... 10
- (b) Explain the steps in Bresenham's line drawing algorithm. ..... 10
- (a) What are the functions of graphics package? Explain. ..... 10(b) A line defined by end points $(1,1)$ and $(2,4)$ is to be translated by 2 units in$X$ direction and 3 units in $Y$ direction and then rotate the translated lineabout origin by $30^{...
- (a) Explain the scan line algorithm. ..... 10
- (b) Formulate matrices for producing orthographic projection of a parallelepiped. ..... 10
- (a) Explain the algorithm for line clipping operation. ..... 10
- (b) Discuss an image space algorithm for hidden surface removal. ..... 10
- (a) Briefly explain the steps in finite element analysis.
- (b) Starting from the first principles derive the stiffness matrix for a 1- D bar element.
- Consider a bar of 200 mm length, $750 \mathrm{~mm}^{2}$ cross sectional area and Young's modulus $2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, as shown in the Fig. 1 . If displacement at node $1, \mathrm{q}_{1}=0.5 \mathrm{~mm}$ and displacement ...
- Consider a bar of 200 mm length, $750 \mathrm{~mm}^{2}$ cross sectional area and Young's modulus $2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, as shown in the Fig. 1 . If displacement at node $1, \mathrm{q}_{1}=0.5 \mathrm{~mm}$ and displacement ...
- Consider a bar of 200 mm length, $750 \mathrm{~mm}^{2}$ cross sectional area and Young's modulus $2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, as shown in the Fig. 1 . If displacement at node $1, \mathrm{q}_{1}=0.5 \mathrm{~mm}$ and displacement ...
- Consider a bar of 200 mm length, $750 \mathrm{~mm}^{2}$ cross sectional area and Young's modulus $2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, as shown in the Fig. 1 . If displacement at node $1, \mathrm{q}_{1}=0.5 \mathrm{~mm}$ and displacement ...
- Consider a bar of 200 mm length, $750 \mathrm{~mm}^{2}$ cross sectional area and Young's modulus $2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}$, as shown in the Fig. 1 . If displacement at node $1, \mathrm{q}_{1}=0.5 \mathrm{~mm}$ and displacement ...