A body of mass " $\mathrm{m}_{1}$ " of a substance of specific heat capacity $\mathrm{c}_{1}$, at a temperature $t_{1}$ is mixed with another body of mass " $\mathrm{m}_{2}$ " of specific heat capacity " $c_{2}$ " at a lower temperature $t_{2}$. Deduce an expression for the temperature of the mixture $t_{3}$.

Explanation

When two bodies are mixed, the heat lost by the hotter body is equal to the heat gained by the cooler body. Therefore, we can write the equation m1 × c1 × (t1 - t3) = m2 × c2 × (t3 - t2). Rearranging this equation, we get m1 × c1 × t1 + m2 × c2 × t2 = (m1 × c1 + m2 × c2) × t3.

Explanation

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