A simple band brake is operated by a lever of length 500 mm . The brake drum has a diameter of 500 mm and the brake band embraces $5 / 8$ of the circumference. One end of the band is attached to the fulcrum of the ever while the other end is attached to a pin on the lever 100 mm from the fulcrum. If the effort applied to the end of the lever is 2 kN and the coefficient of friction is 0.25 , find the maximum braking torque on the drum. OR
Explanation
The problem involves the calculation of maximum braking torque on the drum for a simple band brake. The maximum braking torque is calculated using the formula (effort * coefficient of friction * radius of drum * (1 + (lever length / radius of drum) * (1 - (brake band circumference / (2 * pi * radius of drum))))) = 4.32 kNm.
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