In a 2 -digit number, the digit at the unit's place is 5 less than the digit at the ten's place. The product of the digits is 36 . Find the number. This section consists of 4 questions of 5 marks each.
Explanation
Let's assume the digit at the ten's place is x. Then, the digit at the unit's place is x - 5. The product of the digits is 36, so we can write the equation: x(x - 5) = 36. Expanding the equation, we get: x^2 - 5x = 36. Rearranging the equation, we get: x^2 - 5x - 36 = 0. Factoring the equation, we get: (x - 12)(x + 3) = 0. This gives us two possible values for x: x = 12 or x = -3. Since the digit at the ten's place cannot be negative, we take x = 12. Therefore, the number is 76.
⬆ Related Topic
📘 Syllabus
📝 Practice Questions
Practice Previous Year Questions →
🤖 Practice with AI
Generate Practice Question Paper →