Prove that $\sqrt{5}$ is an irrational number.
Explanation
To prove that √5 is irrational, we can assume the opposite, i.e., √5 = a/b, where a and b are integers. Then, we can square both sides to get 5 = a^2/b^2, which implies that 5 is a perfect square. However, this is a contradiction, since 5 is not a perfect square. Therefore, our assumption is wrong, and √5 is indeed an irrational number.
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