Which term of the A.P. $-29,-26,-23, \ldots, 61$ is 16 ?
Explanation
The given A.P. is -29, -26, -23, ..., 61. The common difference is -26 - (-29) = -26 + 29 = 3. The nth term of an A.P. is given by a_n = a + (n - 1)d, where a is the first term and d is the common difference. Here, a = -29 and d = 3. We need to find the value of n for which a_n = 16. So, we have -29 + (n - 1)3 = 16. Simplifying, we get (n - 1)3 = 45, which gives n - 1 = 15, and n = 16.
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